(x+2i)(x+1)=0

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Solution for (x+2i)(x+1)=0 equation:


Simplifying
(x + 2i)(x + 1) = 0

Reorder the terms:
(2i + x)(x + 1) = 0

Reorder the terms:
(2i + x)(1 + x) = 0

Multiply (2i + x) * (1 + x)
(2i * (1 + x) + x(1 + x)) = 0
((1 * 2i + x * 2i) + x(1 + x)) = 0
((2i + 2ix) + x(1 + x)) = 0
(2i + 2ix + (1 * x + x * x)) = 0
(2i + 2ix + (1x + x2)) = 0
(2i + 2ix + 1x + x2) = 0

Solving
2i + 2ix + 1x + x2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1x' to each side of the equation.
2i + 2ix + 1x + -1x + x2 = 0 + -1x

Combine like terms: 1x + -1x = 0
2i + 2ix + 0 + x2 = 0 + -1x
2i + 2ix + x2 = 0 + -1x
Remove the zero:
2i + 2ix + x2 = -1x

Add '-1x2' to each side of the equation.
2i + 2ix + x2 + -1x2 = -1x + -1x2

Combine like terms: x2 + -1x2 = 0
2i + 2ix + 0 = -1x + -1x2
2i + 2ix = -1x + -1x2

Reorder the terms:
2i + 2ix + x + x2 = -1x + x + -1x2 + x2

Combine like terms: -1x + x = 0
2i + 2ix + x + x2 = 0 + -1x2 + x2
2i + 2ix + x + x2 = -1x2 + x2

Combine like terms: -1x2 + x2 = 0
2i + 2ix + x + x2 = 0

The solution to this equation could not be determined.

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