(x+2i)(x-1)=0

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Solution for (x+2i)(x-1)=0 equation:


Simplifying
(x + 2i)(x + -1) = 0

Reorder the terms:
(2i + x)(x + -1) = 0

Reorder the terms:
(2i + x)(-1 + x) = 0

Multiply (2i + x) * (-1 + x)
(2i * (-1 + x) + x(-1 + x)) = 0
((-1 * 2i + x * 2i) + x(-1 + x)) = 0
((-2i + 2ix) + x(-1 + x)) = 0
(-2i + 2ix + (-1 * x + x * x)) = 0
(-2i + 2ix + (-1x + x2)) = 0
(-2i + 2ix + -1x + x2) = 0

Solving
-2i + 2ix + -1x + x2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add 'x' to each side of the equation.
-2i + 2ix + -1x + x + x2 = 0 + x

Combine like terms: -1x + x = 0
-2i + 2ix + 0 + x2 = 0 + x
-2i + 2ix + x2 = 0 + x
Remove the zero:
-2i + 2ix + x2 = x

Add '-1x2' to each side of the equation.
-2i + 2ix + x2 + -1x2 = x + -1x2

Combine like terms: x2 + -1x2 = 0
-2i + 2ix + 0 = x + -1x2
-2i + 2ix = x + -1x2

Reorder the terms:
-2i + 2ix + -1x + x2 = x + -1x + -1x2 + x2

Combine like terms: x + -1x = 0
-2i + 2ix + -1x + x2 = 0 + -1x2 + x2
-2i + 2ix + -1x + x2 = -1x2 + x2

Combine like terms: -1x2 + x2 = 0
-2i + 2ix + -1x + x2 = 0

The solution to this equation could not be determined.

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