(x+2)/9=2-(x+4)/2

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Solution for (x+2)/9=2-(x+4)/2 equation: 



(x+2)/9=2-(x+4)/2

We move all terms to the left:

(x+2)/9-(2-(x+4)/2)=0

We calculate fractions


x/()+(-(2-(x+4)*9)/()=0



We calculate terms in parentheses: +(-(2-(x+4)*9)/(), so:

-(2-(x+4)*9)/(

We multiply all the terms by the denominator


-(2-(x+4)*9)



We calculate terms in parentheses: -(2-(x+4)*9), so:

2-(x+4)*9

determiningTheFunctionDomain
-(x+4)*9+2

We multiply parentheses

-9x-36+2

We add all the numbers together, and all the variables

-9x-34

Back to the equation:

-(-9x-34)



We get rid of parentheses

9x+34

Back to the equation:

+(9x+34)



We get rid of parentheses

x/()+9x+34=0

We multiply all the terms by the denominator


x+9x*()+34*()=0

We add all the numbers together, and all the variables

x+9x*()=0

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