(x+2)/7=(3x+6)/5

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Solution for (x+2)/7=(3x+6)/5 equation: 



(x+2)/7=(3x+6)/5

We move all terms to the left:

(x+2)/7-((3x+6)/5)=0

We calculate fractions


x/()+(-((3x+6)*7)/()=0



We calculate terms in parentheses: +(-((3x+6)*7)/(), so:

-((3x+6)*7)/(

We multiply all the terms by the denominator


-((3x+6)*7)



We calculate terms in parentheses: -((3x+6)*7), so:

(3x+6)*7

We multiply parentheses

21x+42

Back to the equation:

-(21x+42)



We get rid of parentheses

-21x-42

Back to the equation:

+(-21x-42)



We get rid of parentheses

x/()-21x-42=0

We multiply all the terms by the denominator


x-21x*()-42*()=0

We add all the numbers together, and all the variables

x-21x*()=0

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