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(x+2)+(x+5)=(x+12)+(x)
We move all terms to the left:
(x+2)+(x+5)-((x+12)+(x))=0
We get rid of parentheses
x+x-((x+12)+x)+2+5=0
We calculate terms in parentheses: -((x+12)+x), so:We add all the numbers together, and all the variables
(x+12)+x
We add all the numbers together, and all the variables
x+(x+12)
We get rid of parentheses
x+x+12
We add all the numbers together, and all the variables
2x+12
Back to the equation:
-(2x+12)
2x-(2x+12)+7=0
We get rid of parentheses
2x-2x-12+7=0
We add all the numbers together, and all the variables
-5!=0
There is no solution for this equation
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