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3(x-2)=15-2(x-7)
We move all terms to the left:
3(x-2)-(15-2(x-7))=0
We multiply parentheses
3x-(15-2(x-7))-6=0
We calculate terms in parentheses: -(15-2(x-7)), so:We get rid of parentheses
15-2(x-7)
determiningTheFunctionDomain -2(x-7)+15
We multiply parentheses
-2x+14+15
We add all the numbers together, and all the variables
-2x+29
Back to the equation:
-(-2x+29)
3x+2x-29-6=0
We add all the numbers together, and all the variables
5x-35=0
We move all terms containing x to the left, all other terms to the right
5x=35
x=35/5
x=7
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