(x+2)+(x+1)=6(x+x+1)-12

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Solution for (x+2)+(x+1)=6(x+x+1)-12 equation: 



(x+2)+(x+1)=6(x+x+1)-12

We move all terms to the left:

(x+2)+(x+1)-(6(x+x+1)-12)=0

We add all the numbers together, and all the variables

(x+2)+(x+1)-(6(2x+1)-12)=0

We get rid of parentheses

x+x-(6(2x+1)-12)+2+1=0



We calculate terms in parentheses: -(6(2x+1)-12), so:

6(2x+1)-12

We multiply parentheses

12x+6-12

We add all the numbers together, and all the variables

12x-6

Back to the equation:

-(12x-6)



We add all the numbers together, and all the variables

2x-(12x-6)+3=0

We get rid of parentheses

2x-12x+6+3=0

We add all the numbers together, and all the variables

-10x+9=0

We move all terms containing x to the left, all other terms to the right

-10x=-9

x=-9/-10

x=9/10

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