(x+2)(x-3)(x+7)(x-8)=336

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Solution for (x+2)(x-3)(x+7)(x-8)=336 equation: 



(x+2)(x-3)(x+7)(x-8)=336

We move all terms to the left:

(x+2)(x-3)(x+7)(x-8)-(336)=0

We multiply parentheses ..

(+x^2-3x+2x-6)(x+7)(x-8)-336=0

We multiply parentheses ..

(+x^2-3x+2x-6)(+x^2-8x+7x-56)-336=0

We move all terms containing x to the left, all other terms to the right

(+x^2-3x+2x-6)(+x^2-8x+7x-56)=336

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