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1/3x-12x=-24
We move all terms to the left:
1/3x-12x-(-24)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
-12x+1/3x+24=0
We multiply all the terms by the denominator
-12x*3x+24*3x+1=0
Wy multiply elements
-36x^2+72x+1=0
a = -36; b = 72; c = +1;
Δ = b2-4ac
Δ = 722-4·(-36)·1
Δ = 5328
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5328}=\sqrt{144*37}=\sqrt{144}*\sqrt{37}=12\sqrt{37}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-12\sqrt{37}}{2*-36}=\frac{-72-12\sqrt{37}}{-72} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+12\sqrt{37}}{2*-36}=\frac{-72+12\sqrt{37}}{-72} $
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