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(x+2)(35/x-3)=18
We move all terms to the left:
(x+2)(35/x-3)-(18)=0
Domain of the equation: x-3)!=0We multiply parentheses ..
x∈R
(+35x^2-3x+70x-6)-18=0
We get rid of parentheses
35x^2-3x+70x-6-18=0
We add all the numbers together, and all the variables
35x^2+67x-24=0
a = 35; b = 67; c = -24;
Δ = b2-4ac
Δ = 672-4·35·(-24)
Δ = 7849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(67)-\sqrt{7849}}{2*35}=\frac{-67-\sqrt{7849}}{70} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(67)+\sqrt{7849}}{2*35}=\frac{-67+\sqrt{7849}}{70} $
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