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(x+2)(35-3x)=18
We move all terms to the left:
(x+2)(35-3x)-(18)=0
We add all the numbers together, and all the variables
(x+2)(-3x+35)-18=0
We multiply parentheses ..
(-3x^2+35x-6x+70)-18=0
We get rid of parentheses
-3x^2+35x-6x+70-18=0
We add all the numbers together, and all the variables
-3x^2+29x+52=0
a = -3; b = 29; c = +52;
Δ = b2-4ac
Δ = 292-4·(-3)·52
Δ = 1465
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(29)-\sqrt{1465}}{2*-3}=\frac{-29-\sqrt{1465}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(29)+\sqrt{1465}}{2*-3}=\frac{-29+\sqrt{1465}}{-6} $
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