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(x+10)(6x-7)=0
We multiply parentheses ..
(+6x^2-7x+60x-70)=0
We get rid of parentheses
6x^2-7x+60x-70=0
We add all the numbers together, and all the variables
6x^2+53x-70=0
a = 6; b = 53; c = -70;
Δ = b2-4ac
Δ = 532-4·6·(-70)
Δ = 4489
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4489}=67$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(53)-67}{2*6}=\frac{-120}{12} =-10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(53)+67}{2*6}=\frac{14}{12} =1+1/6 $
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