4(3x-3)-5=4(x-4)+15

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Solution for 4(3x-3)-5=4(x-4)+15 equation: 



4(3x-3)-5=4(x-4)+15

We move all terms to the left:

4(3x-3)-5-(4(x-4)+15)=0

We multiply parentheses

12x-(4(x-4)+15)-12-5=0



We calculate terms in parentheses: -(4(x-4)+15), so:

4(x-4)+15

We multiply parentheses

4x-16+15

We add all the numbers together, and all the variables

4x-1

Back to the equation:

-(4x-1)



We add all the numbers together, and all the variables

12x-(4x-1)-17=0

We get rid of parentheses

12x-4x+1-17=0

We add all the numbers together, and all the variables

8x-16=0

We move all terms containing x to the left, all other terms to the right

8x=16

x=16/8

x=2

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