(x+1)/3=2-(x+1)/7

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Solution for (x+1)/3=2-(x+1)/7 equation:



(x+1)/3=2-(x+1)/7
We move all terms to the left:
(x+1)/3-(2-(x+1)/7)=0
We calculate fractions
x/()+(-(2-(x+1)*3)/()=0
We calculate terms in parentheses: +(-(2-(x+1)*3)/(), so:
-(2-(x+1)*3)/(
We multiply all the terms by the denominator
-(2-(x+1)*3)
We calculate terms in parentheses: -(2-(x+1)*3), so:
2-(x+1)*3
determiningTheFunctionDomain -(x+1)*3+2
We multiply parentheses
-3x-3+2
We add all the numbers together, and all the variables
-3x-1
Back to the equation:
-(-3x-1)
We get rid of parentheses
3x+1
Back to the equation:
+(3x+1)
We get rid of parentheses
x/()+3x+1=0
We multiply all the terms by the denominator
x+3x*()+1*()=0
We add all the numbers together, and all the variables
x+3x*()=0

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