(3/y)=(7/40)

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Solution for (3/y)=(7/40) equation: 



(3/y)=(7/40)

We move all terms to the left:

(3/y)-((7/40))=0



Domain of the equation: y)!=0

y!=0/1

y!=0

y∈R



We add all the numbers together, and all the variables

(+3/y)-((+7/40))=0

We get rid of parentheses

3/y-((+7/40))=0

We calculate fractions


()/40y^2+(-((+7*y)/40y^2=0

We add all the numbers together, and all the variables

()/40y^2+(-((+7y)/40y^2=0

We multiply all the terms by the denominator


(-((+7y)+()=0



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