(x+1)/(x-3)=4-12/(x-3)(x+1)

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Solution for (x+1)/(x-3)=4-12/(x-3)(x+1) equation: 


D( x )

x-3 = 0

x-3 = 0

x-3 = 0

x-3 = 0 // + 3

x = 3

x in (-oo:3) U (3:+oo)

(x+1)/(x-3) = 4-((12/(x-3))*(x+1)) // - 4-((12/(x-3))*(x+1))

(x+1)/(x-3)+(12/(x-3))*(x+1)-4 = 0

(x+1)/(x-3)+(12*(x+1))/(x-3)-4 = 0

(x+1)/(x-3)+(12*(x+1))/(x-3)+(-4*(x-3))/(x-3) = 0

12*(x+1)-4*(x-3)+x+1 = 0

13*x-4*x+12+13 = 0

9*x+25 = 0

(9*x+25)/(x-3) = 0

(9*x+25)/(x-3) = 0 // * x-3

9*x+25 = 0

9*x+25 = 0 // - 25

9*x = -25 // : 9

x = -25/9

x = -25/9

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