3(x+1)-(x+1)=2

Solution for 3(x+1)-(x+1)=2 equation:

Simplifying
3(x + 1) + -1(x + 1) = 2

Reorder the terms:
3(1 + x) + -1(x + 1) = 2
(1 * 3 + x * 3) + -1(x + 1) = 2
(3 + 3x) + -1(x + 1) = 2

Reorder the terms:
3 + 3x + -1(1 + x) = 2
3 + 3x + (1 * -1 + x * -1) = 2
3 + 3x + (-1 + -1x) = 2

Reorder the terms:
3 + -1 + 3x + -1x = 2

Combine like terms: 3 + -1 = 2
2 + 3x + -1x = 2

Combine like terms: 3x + -1x = 2x
2 + 2x = 2

Add '-2' to each side of the equation.
2 + -2 + 2x = 2 + -2

Combine like terms: 2 + -2 = 0
0 + 2x = 2 + -2
2x = 2 + -2

Combine like terms: 2 + -2 = 0
2x = 0

Solving
2x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '2'.
x = 0

Simplifying
x = 0