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(x+1)/(x+2)=2/3
We move all terms to the left:
(x+1)/(x+2)-(2/3)=0
Domain of the equation: (x+2)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
x!=-2
x∈R
(x+1)/(x+2)-(+2/3)=0
We get rid of parentheses
(x+1)/(x+2)-2/3=0
We calculate fractions
(3x+3)/(3x+6)+(-2x-4)/(3x+6)=0
We multiply all the terms by the denominator
(3x+3)+(-2x-4)=0
We get rid of parentheses
3x-2x+3-4=0
We add all the numbers together, and all the variables
x-1=0
We move all terms containing x to the left, all other terms to the right
x=1
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