(x+1)(x-3)+8x=2x+(x+5)(x+3)

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Solution for (x+1)(x-3)+8x=2x+(x+5)(x+3) equation: 



(x+1)(x-3)+8x=2x+(x+5)(x+3)

We move all terms to the left:

(x+1)(x-3)+8x-(2x+(x+5)(x+3))=0

We add all the numbers together, and all the variables

8x+(x+1)(x-3)-(2x+(x+5)(x+3))=0

We multiply parentheses ..

(+x^2-3x+x-3)+8x-(2x+(x+5)(x+3))=0



We calculate terms in parentheses: -(2x+(x+5)(x+3)), so:

2x+(x+5)(x+3)

We multiply parentheses ..

(+x^2+3x+5x+15)+2x

We get rid of parentheses

x^2+3x+5x+2x+15

We add all the numbers together, and all the variables

x^2+10x+15

Back to the equation:

-(x^2+10x+15)



We get rid of parentheses

x^2-x^2-3x+x+8x-10x-3-15=0

We add all the numbers together, and all the variables

-4x-18=0

We move all terms containing x to the left, all other terms to the right

-4x=18

x=18/-4

x=-4+1/2

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