35=(5/7)c

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Solution for 35=(5/7)c equation: 



35=(5/7)c

We move all terms to the left:

35-((5/7)c)=0



Domain of the equation: 7)c)!=0

c!=0/1

c!=0

c∈R



We add all the numbers together, and all the variables

-((+5/7)c)+35=0

We multiply all the terms by the denominator


-((+5+35*7)c)=0



We calculate terms in parentheses: -((+5+35*7)c), so:

(+5+35*7)c

We add all the numbers together, and all the variables

250c

Back to the equation:

-(250c)



c=0/-250

c=0

Równanie nie ma rozwiązania

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