(x+1)(x-2)=x2+4x+8

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Solution for (x+1)(x-2)=x2+4x+8 equation: 



(x+1)(x-2)=x2+4x+8

We move all terms to the left:

(x+1)(x-2)-(x2+4x+8)=0

We add all the numbers together, and all the variables

-(+x^2+4x+8)+(x+1)(x-2)=0

We get rid of parentheses

-x^2-4x+(x+1)(x-2)-8=0

We multiply parentheses ..

-x^2+(+x^2-2x+x-2)-4x-8=0

We add all the numbers together, and all the variables

-1x^2+(+x^2-2x+x-2)-4x-8=0

We get rid of parentheses

-1x^2+x^2-2x+x-4x-2-8=0

We add all the numbers together, and all the variables

-5x-10=0

We move all terms containing x to the left, all other terms to the right

-5x=10

x=10/-5

x=-2

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