3(2w+3)=4w-2)+20

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Solution for 3(2w+3)=4w-2)+20 equation: 



3(2w+3)=4w-2)+20

We move all terms to the left:

3(2w+3)-(4w-2)+20)=0

We add all the numbers together, and all the variables

3(2w+3)-(4w-2)=0

We multiply parentheses

6w-(4w-2)+9=0

We get rid of parentheses

6w-4w+2+9=0

We add all the numbers together, and all the variables

2w+11=0

We move all terms containing w to the left, all other terms to the right

2w=-11

w=-11/2

w=-5+1/2

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