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(x+1)(x-1)+2x=x2-5
We move all terms to the left:
(x+1)(x-1)+2x-(x2-5)=0
We add all the numbers together, and all the variables
-(+x^2-5)+(x+1)(x-1)+2x=0
We add all the numbers together, and all the variables
-(+x^2-5)+2x+(x+1)(x-1)=0
We use the square of the difference formula
-(+x^2-5)+x^2+2x-1=0
We get rid of parentheses
-x^2+x^2+2x+5-1=0
We add all the numbers together, and all the variables
2x+4=0
We move all terms containing x to the left, all other terms to the right
2x=-4
x=-4/2
x=-2
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