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(13/24)x=26
We move all terms to the left:
(13/24)x-(26)=0
Domain of the equation: 24)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+13/24)x-26=0
We multiply parentheses
13x^2-26=0
a = 13; b = 0; c = -26;
Δ = b2-4ac
Δ = 02-4·13·(-26)
Δ = 1352
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1352}=\sqrt{676*2}=\sqrt{676}*\sqrt{2}=26\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-26\sqrt{2}}{2*13}=\frac{0-26\sqrt{2}}{26} =-\frac{26\sqrt{2}}{26} =-\sqrt{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+26\sqrt{2}}{2*13}=\frac{0+26\sqrt{2}}{26} =\frac{26\sqrt{2}}{26} =\sqrt{2} $
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