(x+1)(4x+8)=(x+1)(4x+8)

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Solution for (x+1)(4x+8)=(x+1)(4x+8) equation: 



(x+1)(4x+8)=(x+1)(4x+8)

We move all terms to the left:

(x+1)(4x+8)-((x+1)(4x+8))=0

We multiply parentheses ..

(+4x^2+8x+4x+8)-((+4x^2+8x+4x+8))=0



We calculate terms in parentheses: -((+4x^2+8x+4x+8)), so:

(+4x^2+8x+4x+8)

We get rid of parentheses

4x^2+8x+4x+8

We add all the numbers together, and all the variables

4x^2+12x+8

Back to the equation:

-(4x^2+12x+8)



We get rid of parentheses

4x^2-4x^2+8x+4x-12x+8-8=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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