4(3+5d)-4=3+2(d-2)

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Solution for 4(3+5d)-4=3+2(d-2) equation: 



4(3+5d)-4=3+2(d-2)

We move all terms to the left:

4(3+5d)-4-(3+2(d-2))=0

We add all the numbers together, and all the variables

4(5d+3)-(3+2(d-2))-4=0

We multiply parentheses

20d-(3+2(d-2))+12-4=0



We calculate terms in parentheses: -(3+2(d-2)), so:

3+2(d-2)

determiningTheFunctionDomain
2(d-2)+3

We multiply parentheses

2d-4+3

We add all the numbers together, and all the variables

2d-1

Back to the equation:

-(2d-1)



We add all the numbers together, and all the variables

20d-(2d-1)+8=0

We get rid of parentheses

20d-2d+1+8=0

We add all the numbers together, and all the variables

18d+9=0

We move all terms containing d to the left, all other terms to the right

18d=-9

d=-9/18

d=-1/2

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