(x+1)(2x-5)=(x-1)(2x+3)

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Solution for (x+1)(2x-5)=(x-1)(2x+3) equation: 



(x+1)(2x-5)=(x-1)(2x+3)

We move all terms to the left:

(x+1)(2x-5)-((x-1)(2x+3))=0

We multiply parentheses ..

(+2x^2-5x+2x-5)-((x-1)(2x+3))=0



We calculate terms in parentheses: -((x-1)(2x+3)), so:

(x-1)(2x+3)

We multiply parentheses ..

(+2x^2+3x-2x-3)

We get rid of parentheses

2x^2+3x-2x-3

We add all the numbers together, and all the variables

2x^2+x-3

Back to the equation:

-(2x^2+x-3)



We get rid of parentheses

2x^2-2x^2-5x+2x-x-5+3=0

We add all the numbers together, and all the variables

-4x-2=0

We move all terms containing x to the left, all other terms to the right

-4x=2

x=2/-4

x=-1/2

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