(2x-3)+(6x-5)=3x+12

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Solution for (2x-3)+(6x-5)=3x+12 equation: 



(2x-3)+(6x-5)=3x+12

We move all terms to the left:

(2x-3)+(6x-5)-(3x+12)=0

We get rid of parentheses

2x+6x-3x-3-5-12=0

We add all the numbers together, and all the variables

5x-20=0

We move all terms containing x to the left, all other terms to the right

5x=20

x=20/5

x=4

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