(x+1)(11+x+1)=(x+4)(1+x+4)

Solution for (x+1)(11+x+1)=(x+4)(1+x+4) equation:

(x+1)(11+x+1)=(x+4)(1+x+4)

We move all terms to the left:

(x+1)(11+x+1)-((x+4)(1+x+4))=0

We add all the numbers together, and all the variables

(x+1)(x+12)-((x+4)(x+5))=0

We multiply parentheses ..

(+x^2+12x+x+12)-((x+4)(x+5))=0


We calculate terms in parentheses: -((x+4)(x+5)), so:

(x+4)(x+5)

We multiply parentheses ..

(+x^2+5x+4x+20)

We get rid of parentheses

x^2+5x+4x+20

We add all the numbers together, and all the variables

x^2+9x+20

Back to the equation:

-(x^2+9x+20)


We get rid of parentheses

x^2-x^2+12x+x-9x+12-20=0

We add all the numbers together, and all the variables

4x-8=0

We move all terms containing x to the left, all other terms to the right

4x=8

x=8/4

x=2