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(2/x)+(2/3)=(8/9)
We move all terms to the left:
(2/x)+(2/3)-((8/9))=0
Domain of the equation: x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+2/x)+(+2/3)-((+8/9))=0
We get rid of parentheses
2/x+2/3-((+8/9))=0
We calculate fractions
162x^2/243x^2+()/243x^2+(-((+8*x*3)/243x^2=0
We multiply all the terms by the denominator
162x^2+(-((+8*x*3)+()=0
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