(x)=x2+14x+16

Solution for (x)=x2+14x+16 equation:

(x)=x2+14x+16

We move all terms to the left:

(x)-(x2+14x+16)=0

We add all the numbers together, and all the variables

-(+x^2+14x+16)+x=0

We get rid of parentheses

-x^2-14x+x-16=0

We add all the numbers together, and all the variables

-1x^2-13x-16=0

a = -1; b = -13; c = -16;
Δ = b2-4ac
Δ = -132-4·(-1)·(-16)
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{105}}{2*-1}=\frac{13-\sqrt{105}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{105}}{2*-1}=\frac{13+\sqrt{105}}{-2}
$