2/3y-7=1/3y+5

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Solution for 2/3y-7=1/3y+5 equation: 



2/3y-7=1/3y+5

We move all terms to the left:

2/3y-7-(1/3y+5)=0



Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R





Domain of the equation: 3y+5)!=0

y∈R



We get rid of parentheses

2/3y-1/3y-5-7=0

We multiply all the terms by the denominator


-5*3y-7*3y+2-1=0

We add all the numbers together, and all the variables

-5*3y-7*3y+1=0

Wy multiply elements

-15y-21y+1=0

We add all the numbers together, and all the variables

-36y+1=0

We move all terms containing y to the left, all other terms to the right

-36y=-1

y=-1/-36

y=1/36

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