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(x)(x)/(1-x)(3-x)=4
We move all terms to the left:
(x)(x)/(1-x)(3-x)-(4)=0
Domain of the equation: (1-x)(3-x)!=0We add all the numbers together, and all the variables
We move all terms containing x to the left, all other terms to the right
-x)(3-x!=-1
x∈R
xx/(-1x+1)(-1x+3)-4=0
We multiply parentheses ..
xx/(+x^2-3x-1x+3)-4=0
We multiply all the terms by the denominator
-4*(+x^2-3x-1x+3)+xx=0
We multiply parentheses
-4x^2+12x+4x+xx-12=0
We add all the numbers together, and all the variables
-4x^2+16x+xx-12=0
We move all terms containing x to the left, all other terms to the right
-4x^2+16x+xx=12
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