35(2x-1)=7(x+4)+3x=

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Solution for 35(2x-1)=7(x+4)+3x= equation: 



35(2x-1)=7(x+4)+3x=

We move all terms to the left:

35(2x-1)-(7(x+4)+3x)=0

We multiply parentheses

70x-(7(x+4)+3x)-35=0



We calculate terms in parentheses: -(7(x+4)+3x), so:

7(x+4)+3x

We add all the numbers together, and all the variables

3x+7(x+4)

We multiply parentheses

3x+7x+28

We add all the numbers together, and all the variables

10x+28

Back to the equation:

-(10x+28)



We get rid of parentheses

70x-10x-28-35=0

We add all the numbers together, and all the variables

60x-63=0

We move all terms containing x to the left, all other terms to the right

60x=63

x=63/60

x=1+1/20

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