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(x)(x+6)=280
We move all terms to the left:
(x)(x+6)-(280)=0
We multiply parentheses
x^2+6x-280=0
a = 1; b = 6; c = -280;
Δ = b2-4ac
Δ = 62-4·1·(-280)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-34}{2*1}=\frac{-40}{2} =-20 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+34}{2*1}=\frac{28}{2} =14 $
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