(w)(w-2)(w+4)=8(w+4)

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Solution for (w)(w-2)(w+4)=8(w+4) equation: 



(w)(w-2)(w+4)=8(w+4)

We move all terms to the left:

(w)(w-2)(w+4)-(8(w+4))=0

We multiply parentheses ..

w(+w^2+4w-2w-8)-(8(w+4))=0



We calculate terms in parentheses: -(8(w+4)), so:

8(w+4)

We multiply parentheses

8w+32

Back to the equation:

-(8w+32)



We multiply parentheses

w^3+4w^2-2w^2-8w-(8w+32)=0

We get rid of parentheses

w^3+4w^2-2w^2-8w-8w-32=0

We do not support ewpression: w^3

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