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5(3x-x)=x-2(8)
We move all terms to the left:
5(3x-x)-(x-2(8))=0
We add all the numbers together, and all the variables
5(+2x)-(x-28)=0
We multiply parentheses
10x-(x-28)=0
We get rid of parentheses
10x-x+28=0
We add all the numbers together, and all the variables
9x+28=0
We move all terms containing x to the left, all other terms to the right
9x=-28
x=-28/9
x=-3+1/9
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