(v-3/v-5)+1=(v-4/v-6)

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Solution for (v-3/v-5)+1=(v-4/v-6) equation: 



(v-3/v-5)+1=(v-4/v-6)

We move all terms to the left:

(v-3/v-5)+1-((v-4/v-6))=0



Domain of the equation: v-5)!=0

v∈R





Domain of the equation: v-6))!=0

v∈R



We get rid of parentheses

v-3/v-((v-4/v-6))-5+1=0

We calculate fractions


v+(-3v)/v^2+(-((v-4*v)/v^2-5+1=0

We add all the numbers together, and all the variables

v+(-3v)/v^2+(-((-3v)/v^2-5+1=0

We calculate fractions

We do not support evpression: v^4

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