(u+1)+7=3(u-2)+2u

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Solution for (u+1)+7=3(u-2)+2u equation: 



(u+1)+7=3(u-2)+2u

We move all terms to the left:

(u+1)+7-(3(u-2)+2u)=0

We get rid of parentheses

u-(3(u-2)+2u)+1+7=0



We calculate terms in parentheses: -(3(u-2)+2u), so:

3(u-2)+2u

We add all the numbers together, and all the variables

2u+3(u-2)

We multiply parentheses

2u+3u-6

We add all the numbers together, and all the variables

5u-6

Back to the equation:

-(5u-6)



We add all the numbers together, and all the variables

u-(5u-6)+8=0

We get rid of parentheses

u-5u+6+8=0

We add all the numbers together, and all the variables

-4u+14=0

We move all terms containing u to the left, all other terms to the right

-4u=-14

u=-14/-4

u=3+1/2

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