4(z-5)=32

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Solution for 4(z-5)=32 equation: 



4(z-5)=32

We move all terms to the left:

4(z-5)-(32)=0

We multiply parentheses

4z-20-32=0

We add all the numbers together, and all the variables

4z-52=0

We move all terms containing z to the left, all other terms to the right

4z=52

z=52/4

z=13

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