(t/30)=(7/10)

Solution for (t/30)=(7/10) equation:

(t/30)=(7/10)

We move all terms to the left:

(t/30)-((7/10))=0

We add all the numbers together, and all the variables

(+t/30)-((+7/10))=0

We get rid of parentheses

t/30-((+7/10))=0

We calculate fractions


10t^2/()+()/()=0

We add all the numbers together, and all the variables

10t^2/()+1=0

We multiply all the terms by the denominator


10t^2+1*()=0

We add all the numbers together, and all the variables

10t^2=0

a = 10; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·10·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{0}{20}=0$