5=2(-3)-b

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Solution for 5=2(-3)-b equation: 



5=2(-3)-b

We move all terms to the left:

5-(2(-3)-b)=0



We calculate terms in parentheses: -(2(-3)-b), so:

2(-3)-b

determiningTheFunctionDomain
-b+2(-3)

We add all the numbers together, and all the variables

-1b-6

Back to the equation:

-(-1b-6)



We get rid of parentheses

1b+6+5=0

We add all the numbers together, and all the variables

b+11=0

We move all terms containing b to the left, all other terms to the right

b=-11

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