(t+1)/2=(2t-3)/6

Solution for (t+1)/2=(2t-3)/6 equation:

(t+1)/2=(2t-3)/6

We move all terms to the left:

(t+1)/2-((2t-3)/6)=0

We calculate fractions


t/()+(-((2t-3)*2)/()=0


We calculate terms in parentheses: +(-((2t-3)*2)/(), so:

-((2t-3)*2)/(

We multiply all the terms by the denominator


-((2t-3)*2)


We calculate terms in parentheses: -((2t-3)*2), so:

(2t-3)*2

We multiply parentheses

4t-6

Back to the equation:

-(4t-6)


We get rid of parentheses

-4t+6

Back to the equation:

+(-4t+6)


We get rid of parentheses

t/()-4t+6=0

We multiply all the terms by the denominator


t-4t*()+6*()=0

We add all the numbers together, and all the variables

t-4t*()=0