7(x-2)=-5(x+3)+40

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Solution for 7(x-2)=-5(x+3)+40 equation: 



7(x-2)=-5(x+3)+40

We move all terms to the left:

7(x-2)-(-5(x+3)+40)=0

We multiply parentheses

7x-(-5(x+3)+40)-14=0



We calculate terms in parentheses: -(-5(x+3)+40), so:

-5(x+3)+40

We multiply parentheses

-5x-15+40

We add all the numbers together, and all the variables

-5x+25

Back to the equation:

-(-5x+25)



We get rid of parentheses

7x+5x-25-14=0

We add all the numbers together, and all the variables

12x-39=0

We move all terms containing x to the left, all other terms to the right

12x=39

x=39/12

x=3+1/4

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