(s+2)(s+2)=-9

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Solution for (s+2)(s+2)=-9 equation: 



(s+2)(s+2)=-9

We move all terms to the left:

(s+2)(s+2)-(-9)=0

We add all the numbers together, and all the variables

(s+2)(s+2)+9=0

We multiply parentheses ..

(+s^2+2s+2s+4)+9=0

We get rid of parentheses

s^2+2s+2s+4+9=0

We add all the numbers together, and all the variables

s^2+4s+13=0

a = 1; b = 4; c = +13;
Δ = b2-4ac
Δ = 42-4·1·13
Δ = -36
Delta is less than zero, so there is no solution for the equation

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