4(z+5)+6=3(z-5)=+6

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Solution for 4(z+5)+6=3(z-5)=+6 equation: 



4(z+5)+6=3(z-5)=+6

We move all terms to the left:

4(z+5)+6-(3(z-5))=0

We multiply parentheses

4z-(3(z-5))+20+6=0



We calculate terms in parentheses: -(3(z-5)), so:

3(z-5)

We multiply parentheses

3z-15

Back to the equation:

-(3z-15)



We add all the numbers together, and all the variables

4z-(3z-15)+26=0

We get rid of parentheses

4z-3z+15+26=0

We add all the numbers together, and all the variables

z+41=0

We move all terms containing z to the left, all other terms to the right

z=-41

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