(r-6)+(3r-3)+(5r)=180

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Solution for (r-6)+(3r-3)+(5r)=180 equation: 



(r-6)+(3r-3)+(5r)=180

We move all terms to the left:

(r-6)+(3r-3)+(5r)-(180)=0

We add all the numbers together, and all the variables

5r+(r-6)+(3r-3)-180=0

We get rid of parentheses

5r+r+3r-6-3-180=0

We add all the numbers together, and all the variables

9r-189=0

We move all terms containing r to the left, all other terms to the right

9r=189

r=189/9

r=21

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