-5/9e-2/3e=-24

Solution for -5/9e-2/3e=-24 equation:

-5/9e-2/3e=-24

We move all terms to the left:

-5/9e-2/3e-(-24)=0


Domain of the equation: 9e!=0

e!=0/9

e!=0

e∈R



Domain of the equation: 3e!=0

e!=0/3

e!=0

e∈R


We add all the numbers together, and all the variables

-5/9e-2/3e+24=0

We calculate fractions


(-15e)/27e^2+(-18e)/27e^2+24=0

We multiply all the terms by the denominator


(-15e)+(-18e)+24*27e^2=0

Wy multiply elements

648e^2+(-15e)+(-18e)=0

We get rid of parentheses

648e^2-15e-18e=0

We add all the numbers together, and all the variables

648e^2-33e=0

a = 648; b = -33; c = 0;
Δ = b2-4ac
Δ = -332-4·648·0
Δ = 1089
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1089}=33$
$e_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-33}{2*648}=\frac{0}{1296}
=0
$
$e_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+33}{2*648}=\frac{66}{1296}
=11/216
$