(n-3)/2=(n+6)/3

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Solution for (n-3)/2=(n+6)/3 equation:



(n-3)/2=(n+6)/3
We move all terms to the left:
(n-3)/2-((n+6)/3)=0
We calculate fractions
n/()+(-((n+6)*2)/()=0
We calculate terms in parentheses: +(-((n+6)*2)/(), so:
-((n+6)*2)/(
We multiply all the terms by the denominator
-((n+6)*2)
We calculate terms in parentheses: -((n+6)*2), so:
(n+6)*2
We multiply parentheses
2n+12
Back to the equation:
-(2n+12)
We get rid of parentheses
-2n-12
Back to the equation:
+(-2n-12)
We get rid of parentheses
n/()-2n-12=0
We multiply all the terms by the denominator
n-2n*()-12*()=0
We add all the numbers together, and all the variables
n-2n*()=0

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