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16/40=x/2x+1
We move all terms to the left:
16/40-(x/2x+1)=0
Domain of the equation: 2x+1)!=0We get rid of parentheses
x∈R
-x/2x-1+16/40=0
We calculate fractions
(-40x)/80x+32x/80x-1=0
We multiply all the terms by the denominator
(-40x)+32x-1*80x=0
We add all the numbers together, and all the variables
32x+(-40x)-1*80x=0
Wy multiply elements
32x+(-40x)-80x=0
We get rid of parentheses
32x-40x-80x=0
We add all the numbers together, and all the variables
-88x=0
x=0/-88
x=0
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